PLEASE HELP, you have to write the equation in y=Mx+b form but you have to also pay attention to the scale of the graph

y = (1/8)x + 23

Explanation:

Given:

The equation of line y = M*x + b

This line pass (0, 23) and (40, 28)

Solve:

23 = M*0 + b

28 = M*40 + b

From 1st equation:

=> b = 23

Subtract 1st equation from 2nd equation:

     5 = M*40

=> M = 5/40 = 1/8

The equation of line:

=> y = (1/8)x + 23

Hope this helps!

:)

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.

the correct answer would be d because the slope is -2/2=1 and the y intercept is at 2 so that is the correction equation