What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 times a times c all over 2 times a? x = the quantity of negative 5 plus or minus the square root of 3 all over 2
x = the quantity of 5 plus or minus the square root of 3 all over 2
x = the quantity of negative 5 plus or minus the square root of 53 all over 2
x = the quantity of 5 plus or minus the square root of 53 all over 2

Using The Almighty Formula (attached)

Note the symbol ^ is used to denote a raise to power

Where from the equation given x^2-5x-7

With a,b,c coefficients

a=1 b=-5 c=-7

From the Almighty Formula

√b^2-4ac=√(-5)^2-4(-7)=√53

Substituting in the Almighty Formula

-(-5) ±√53/2(1)= 5±√53/2

x=5+√53/2 and x=5-√53/2

x = the quantity of 5 plus or minus the square root of 53 all over 2

Step-by-step explanation:

took the quiz

answer: about 22.67

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752