According to the National Center for Health Statistics, in 1990, 28 % of babies in the United States were born to parents who were not married. Throughout the 1990s, this increased by approximately 0.6 % per year. If this trend continues, in which year will 76 % of babies be born out of wedlock?

76 % of babies will be born out of wedlock in the year

Step-by-step explanation:

Given:  In 1990, 28 % of babies in the United States were born to parents who were not married. This increased by approximately 0.6 % per year.

To find: year when 76 % of babies born out of wedlock

Solution:

A sequence is said to be in arithmetic progression if the difference between the terms is same.

For a sequence with first term as 'a' and common difference as 'd', the nth term is given by

The given situation also forms an arithmetic progression with  

Also, put

So,

So, 76 % of babies will be born out of wedlock in the year

step-by-step explanation:

ad = ae + ed = y + 7

similar triangles therefor

ac/ab = ad/ae

6/4 = (y + 7) / y

cross multiply

6y = 4(y + 7)

6y = 4y + 28

2y = 28

y = 14

step-by-step explanation: