Event Q is more likely to occur than Event T. If P(Event T) = 1/2, what is a possible probability of Event Q? A)1/4
B)1/2
C)2/3
D)It cannot be determined.

i am gonna say D

Step-by-step explanation:

because well you don't what the total or the outcome is

correct me if i am wrong

c. y = 1/4 x + 5

step-by-step explanation:

first, put the equation of the line on the graph into slope-intercept form

(y = mx + b):   y = -4x + 8

second, a perpendicular line has to have "an opposite/reciprocal slope" to the original slope. so, find the "m" value in your original equation (it's -4, right? )

original slope: m = -4   perpendicular slope: change the sign to its opposite and find the reciprocal ("flip" the number)

new slope is now positive (b/c the original slope was negative 4), and it's 1/4 (not the original slope of 4 or 4/1)

the answer is two. hope this !