Given the equation (x - 13) ^ 2 + y ^ 2 = 64 identify the center and radius

radius is 8; center is at (13, 0).

Step-by-step explanation:

Compare the given  (x - 13) ^ 2 + y ^ 2 = 64 to:

                                  (x - h)^2 + (y - k)^2 = r^2.  (h, k) represents the center

                                                                             and r the radius.

Since 64 = r^2, r = the radius = 8 units  = r

We also see that h = 13 and k = 0.  

Thus, the center of the given circle is (13, 0).

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i hope this answer !

"stay and stay proud! " - zalgo

the 2 figures are congruent bc if you reflect abcd over the y axis then over the d axis the figures overlap