A ball thrown into the air from a roof 15 feet above the ground with an initial vertical velocity of 30 ft/sec can be modeled by the equation: . How long will the ball be in the air? What is it’s maximum height?

Total time of flight= 6.3 s

Total Max height= 60.87ft

Step-by-step explanation:

Height above ground = 15ft

Velocity=30ft/sec

Angle = 90°

Max height traveled= U²Sin²tita/2g

Max height traveled= ( 30²*1²)/(2*9.81)

Max height traveled= 900/19.62

Max height traveled= 45.87 ft

Total Max height= 15+45.87= 60.87ft

Time travel to Max height

=( usin90)/g

Time travel to initial position

= (30*sin90)/9.81

= 3.1 s

Time to travel to the ground from Max height

H = 1/2gt²

60.87= 1/2 * 9.81*t²

(60.87*2)/9.81= t²

3.5 = t

Total time of flight = 3.5+3.1

Total time of flight= 6.3 s

its 4 because 2 times 2 is 4, if you double the number two you get four

your answer is the frist one

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