A circle has a radius of $14.$ Let $\overline{AB}$ be a chord of the circle, such that $AB = 12$. What is the distance between the chord and the center of the circle?

7.2

Step-by-step explanation:

The radius of the circle is 14.

The length of the chord is 12.

Half the length of the chord and radius form a right angled triangle as shown in the diagram below.

We need to find one of the sides of the triangle, d in the diagram.

Using Pythagoras rule:

The distance between the chord and the center of the circle is 7.2

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet