A circle is centered at O(0,0)O(0,0)O, left parenthesis, 0, comma, 0, right parenthesis and has a radius of \sqrt{29} 29



square root of, 29, end square root.

Where does the point T(5,-2)T(5,−2)T, left parenthesis, 5, comma, minus, 2, right parenthesis lie?

Point T is on the circle

Step-by-step explanation:

To check where the point lies, we need to find its distance to the center of the circle.

The distance between two points (x1, y1) and (x2, y2) is given by:

If the first point is O(0,0) and the second is T(5, -2), we have:

The distance between the points is equal the radius of the circle, that means the point T is on the circle.

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: