A fair coin is tossed, and a marble is chosen from the bag whose contents are shown below. 3 red marbles, 3 blue marbles, and 4 green marbles. What is the probability of the coin landing heads up and a blue (B) marble being randomly selected?

3/20

Step-by-step explanation:

Red = 3

Blue = 3

Green = 4

Total = 3+3+4 = 10

Pr (red) = 3/10

Pr blue) = 3/10

Pr (green) = 4/10

Where Pr = probability

You either have a head or a tail when tossing a coin

Probability of having head = 1/2

Probability of having tail = 1/2

The probability of the coin landing heads up and blue marble = Probability of head ×Pr (blue)

= 1/2 × 3/10

the probability of the coin landing heads up and blue marble = 3/20

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1