What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form? Quadratic formula: x= -b IVb2 - 400
20
x = 5110/5
N
x= -5110,5
N
0 x = -52/5
o x=575

   x  =  

Step-by-step explanation:

Given equation f(x) = x² + 5 x +5

The roots of the Quadratic equation   ax²+bx+c =0 are

Given equation f(x) = x² + 5 x +5

comparing           ax²+bx+c =0 is

                a = 1 , b = 5 and c = 5

            x  =  

             x  = -7.76 ,  x = -2.76 ,

if x decreases by 4 then y increases by 10

step-by-step explanation:

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