Find the solutions to the system of equations algebraically.
x2 + y2 = 25
y = -2x + 5

x = 0 or x = 4

Step-by-step explanation:

x² + y² = 25 and y = -2x + 5

Here,

x² + y² = 25 ...(1)

Now,

Put the value of y = -2x + 5 in equation (1)

we get,

x² + (-2x + 5)² = 25

x² + {(-2x)² + 2(-2x) (5) + (5)²} = 25

x² + {4x² - 20x + 25} = 25

x² + 4x² - 20x + 25 = 25

5x² - 20x = 25 - 25

5x² - 20x = 0

5x(x - 4) = 0

5x = 0 or x - 4 = 0

x = 0/5 or x = 4

x = 0 or x = 4

did you get the answer yet?

step-by-step explanation: