Solve: A rock is thrown upward with an initial velocity of 16 ft/s from an initial height of 5 ft. Write a quadratic function equation that describes the height h at time t.
Write this polynomial in standard form. ax2 + bx + c a≠ 0
Find the maximum height.
Be sure to answer the question using the correct units.
Write a quadratic function equation that describes the height h at time t.

h\left(t\right)=-16t^2+v_0t+h_0
h(t)=−16t
2
+v
0

t+h
0

5t² - 16t + h =0

Step-by-step explanation:

During upward projection the final velocity is zero, and the gravitational acceleration is -10 m/s² (against the gravity).

Therefore; using the equation;

S = 1/2gt² + ut

Where s is the height h, g is gravitational acceleration, and t is the time and u is the initial velocity u, is 16 ft/s.

Thus; h= 1/2(-10)t² + 16t

We get; h = -5t² + 16t

Therefore; the quadratic equation is 5t² - 16t + h =0

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∠lno ≅ ∠lnm

∠oln ≅ ∠mln

step-by-step explanation:

given   that triangle lno is congruent to triangle lnm.

we have to fill up the blanks in the given question.

according to above order of congruency   kept in mind we can say that

∠lno ≅ ∠lnm

∠oln ≅ ∠mln

ln ≅ ln due to common in both.

hence, by sas congruency,

the side angle side rule   states that if two sides and the included angle of one triangle are congruent to another triangle, then these two triangles are congruent.

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