In rectangle $EFGH$, $EH = 3$ and $EF = 4$. Let $M$ be the midpoint of $\overline{EF}$, and let $X$ be a point such that $MH = MX$ and $\angle MHX = 72^\circ$, as shown below. Find $\angle XGH$, in degrees. [asy] unitsize(1 cm); pair A, B, C, D, M, X; A = (0,3); B = (4,3); C = (4,0); D = (0,0); M = (A + B)/2; X = rotate(26,M)*(D); draw(A--B--C--D--cycle); draw(D--M--X--cycle); draw(C--X); label("$E$", A, NW); label("$F$", B, NE); label("$G$", C, SE); label("$H$", D, SW); label("$M$", M, N); label("$X$", X, S); [/asy]

step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5

19.

step-by-step explanation:

you add the 9 in the tens column since it is a single digit and 9 plus zero is 9 so it is 19

$5.41

step-by-step explanation:

$20 - $14.51 = $5.49.