In ΔPQR, the measure of ∠R=90°, the measure of ∠Q=22°, and PQ = 9.2 feet. Find the length of RP to the nearest tenth of a foot.

been looking for the answer havent been able to find it   but good luck with it

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !