Please please help According to the probability distribution below, what is the expected value of X? X 0 1 2 3 4 5 P(X) 0.3 0.2 0.16 0.2 0.04 0.1 A.) The expected value is 0.1 B.) The expected value is 5 C.) The expected value is 2.5 D.) The expected value is 1.78

D.) The expected value is 1.78

Step-by-step explanation:

The expected value of a probability distribution is evaluated using the formula.

Expected Value,

Therefore, from the given probability distribution, we have:

E(X)=(0*0.3)+(1*0.2)+(2*0.16)+(3*0.2)+(4*0.04)+(5*0.1)

E(X)=1.78

The Expected value of X is 1.78.

The correct option is D.

hello from mrbilldoesmath!

answer:

a(n) - a(n-1) -3

discussion:

this ones a bit interesting. given a(n) = 5 - 3n consider this:

a(n-1) = 5 - 3(n-1)

          = (5 - 3n) + 3             => but a(n) = 5 - 3n, the first term

          = a(n)   + 3                 => subtract 3 from both sides

a(n-1) -3 = a(n)  

or

a(n) - a(n-1) -3

you,

mrb