A theater group made appearances in two cities. The hotel charge before tax in the second city was $1500 lower than in the first. The tax in the staty was 10%, and the tax in the second city was 5%. The total hotel tax paid for the two cities was $600. How much was the hotel charge in each oty before tax?

The Hotel charge without tax in first city is $3500 and The hotel charge before tax in the second city is 2000

Step-by-step explanation:

Let x be the hotel charge without tax in first city

We are given that The hotel charge before tax in the second city was $1500 lower than in the first.

So, Hotel  charge without tax in second city =x-1500

Tax% in first city = 10%

So, tax in first city = 0.1x

Tax% in second city =5%

So, tax in second city = 0.05(x-1500)

We are given that The total hotel tax paid for the two cities was $600.

So,0.1x+0.05(x-1500)=600

0.1x+0.05x+75=600

0.15x=600-75

x=3500

Hotel charge without tax in first city = $3500

The hotel charge before tax in the second city =x-1500=3500-1500=2000

Hence The Hotel charge without tax in first city is $3500 and The hotel charge before tax in the second city is 2000

after simplifying it i got: -36.25 as my answer. hope that !

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!