What is the equation of the line perpendicular to y=2/3x + 1 that passes through the point (12,-6) ?

y=-3/2x+12

Step-by-step explanation:

perpendicular lines their gradient multiply to form -1 thus gradient line 1=2/3

gradient line 2= -3/2

equation= y=mx+c where m represents gradient

y-(-6)/x-12=-3/2

y+6/x-12=-3/2

y+6=-3/2(x-12)

y+6=-3/2x+18

y= -3/2x+18-6

y=-3/2x+12

answer: b.48 for

step-by-step explanation:

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step-by-step explanation:

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