What is the diameter of a sphere with a volume of 6329\text{ ft}^3,6329 ft 3

, to the nearest tenth of a foot?

Diameter = 22.9 ft

Step-by-step explanation:

We are told that volume of the sphere is 6329 ft³

Now formula for volume of sphere is given as;

V = (4/3)πr³

Thus,

(4/3)πr³ = 6329

Multiply both sides by 3/4 to get;

πr³ = (6329) * 3/4

πr³ = 4746.75

Divide both sides by π to obtain;

r³ = 4746.75/π

r = ∛(4746.75/π)

r = 11.4749 ft

Now, diameter = 2 x radius

Diameter = 2 × 11.4749

Diameter = 22.9498 ft

Approximating to a tenth of a feet gives;

Diameter = 22.9 ft

i think the answer is b.

step-by-step explanation:

not 100% sure though.

a

step-by-step explanation: