Which is the equation of the parabola? (will give brainiest) coordinate plane with a parabola facing up with vertex at 4 comma 2, the point 4 comma 6 and a horizontal line going through 0 comma negative 2

y = one sixteenth(x − 4)2 + 2
y = one sixteenth(x + 4)2 − 2
y = −one sixteenth(x − 2)2 + 4
y = −one sixteenth(x + 2)2 − 4

answer: i'm not going to give you the answer, but some hints to work it out.

step-by-step explanation: so, if there is a straight line that means that the line angle is 180°. so we subtract the 2 angle measures provided, (15 and 38) from 180. so the answer is 180 - (38 + 15). (you have to solve the equation)

a .4y4

hope this !

where did you get them? if you picked from the grass, is is probably poisonous.

step-by-step explanation:

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15