C=0.25(L−1200) The cost, C, in dollars, to the holder of a liability insurance account given a total liability of L dollars is given by the equation above as long as C is positive. By how many dollars does the liability increase when the cost to the holder increases by 1 dollar?

c 1 hour

step-by-step explanation:

m = 2e

m = 2 so 2 = 2e

1 = e

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.

600,000,000,000, or 6e14

step-by-step explanation:

hello! just here for points! though i wish i knew!