PLEASEEE ANSWER I NEED HELP NOW Find the probability of
1: choosing a yellow marble from a bag that contains 6 yellow marbles and 8 red marbles,
and
2: flipping a coin and it showing heads.

1:

2:

Step-by-step explanation:

1: the number of yellow marbles is 6

  the number of marbles in the bag is 14

  the probability of yellow marbles out of the bag is

number of yellow marbles over number of marbles in the bag

2: there are only two sides

one head and one tail

head over tail is

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?