There are 19 people on a basketball team, and the coach needs to choose 5 to put into
a game. How many different possible ways can the coach choose a team of 5 if each
person has an equal chance of being selected?

197676 diff possible ways

Step-by-step explanation:

Combination because order doesn't matter.

19!/(19-5)!*5!=19!/14!*5!=19*18*17*16*15*14!/14!*5!=19*18*17*17*16*15/5!=23721120/5*4*3*2=23721120/120=197676

no

step-by-step explanation:

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.