X = 7 – 3y

2(7 – 3y) + 4y = 8

14 – 6y + 4y = 8

14 – 2y = 8

–2y = –6

y = 3

x + 3(3) = 7

(
,
)

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: 48

just remember to use pemdas:

parentheses

expressions

multiplication

division

addition

subtraction

if you need just tell me and i will come to the rescue.

step-by-step explanation:

i believe the answer is 323 ft

step-by-step explanation: