What is the solution set to the equation x^2+6x+3=0

That is a quadratic equation in which

a = 1

b = 6

c = 3

The quadratic formula is:

x = [-b +- sqr root (b^2 -4*a*c)] / 2*a

x = [-6 +- sqr root (36 -4 * 1 * 3)] / 2

x1 = [-6 + sqr root (24)] / 2

x2 = [-6 - sqr root (24)] / 2

Step-by-step explanation:

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