If 108 people attend a concert and tickets for adults cost $4 while tickets for children cost $2 and total receipts for the concert was $328, how many of each went to the concert?

Answer method 1

81 adults and 2 child.

Answer method 2

Therefore  69 adults came and 60 children came. Because 18 children did not pay we have 129-18 = 108 attending

69 : 60 = 276: 120  = 3.02 distribution.

69 x £4 = $276 + 60-18 = 42 = 42 x 2 = $84

Combined = $276+$84 = $360

We find that an extra 8 adults didnt pay either.

Making this  69 adults and 60 children where 8 adults didn't pay and 18 children didn't pay. This way this create an average 3.02 for the 108 people attending.

3.02 x 108 =  $326

80 adults and 8 child

We use ratio of 108 attendees = 328/108 = 3.03 average price which shows ratio  child to adult 1:2

31 adult +42 child = $124 and $82 children = $208 children

38 more adults = 38 x 4 = 120 + 36 = $156 = (38 +18 children) = $156

= $364 - 36 = 6 child not paying = 12 and  6 adults not paying = 21

Therefore  69 adults came and 60 children came. Because 18 children did not pay we have 129-18 = 108 attending

of 48 paying and attending and the other 40 children potentially being non payers and part of

Step-by-step explanation:

4+2 = 6

8+2 = 10

4+4 = 8

We look for 80+ 28 and see 8+2 accounts for 4 adults 2 child = $20

We minus the 20 in workings and realize only when we work out 80 x 4 = 320 that only 2 child was needed and not 6 child for $12 of the 28. Because of me thinking 28 was a distribution, such resource of 4 + 1 adults became just 1 extra adult and 1 extra child.

Simply as I was chasing distribution of $24

8 of 24 was kept as

8 accounts for 1 adult and 2 child. = $8

80 accounts for 60 x $4 adults = $240 + 20 x 4 = $80

240+80=320

= $320 +$20 + $8 (-$20) = $328

Here we did not have to count back to find the correct amount only go steady with 80 distribution for 81 adults and only 2 child.

idk

step-by-step explanation: