The following is an incorrect flowchart proving that point L, lying on line LM which is a perpendicular bisector of segment JK, is equidistant from points J and K:

Segment JK intersects line LM at point N.

Line LM is a perpendicular bisector of segment JK; Given. Two arrows are drawn from this statement to the following two statements. Angle LNK equals 90 degrees and angle LNJ equals 90 degrees; Definition of a Perpendicular Bisector. Segment JN is congruent to segment NK; Definition of a Perpendicular Bisector. Angle LNK is congruent to angle LNJ; Definition of Congruence. Segment LN is congruent to segment LN; Reflexive Property of Equality. Draw segment JL and segment KL; by Construction. Four arrows from the previous four statements are drawn to the statement triangle JNL is congruent to triangle KNL; Side Angle Side, SAS, Postulate. An arrow from this statement is drawn to the statement segment JL is congruent to segment KL; Corresponding Parts of Congruent Triangles are Congruent CPCTC. An arrow from this statement is drawn to JL equals KL; Definition of Congruence. An arrow from this statement is drawn to Point L is equidistant from points J and K; Definition of Equidistant.

What is the error in this flowchart?

An arrow is missing between ∠LNK = 90° and ∠LNJ = 90° and ∠LNK ≅ ∠LNJ.
JL and KL are equal in length, according to the definition of a midpoint.
An arrow is missing between the given statement and ∠LNK ≅ ∠LNJ.
Point L is equidistant from points J and N, not J and K.

answer set (b) 0.5, 3/4 80% is in order from least to greatest.  

step-by-step explanation:

in order to compare rational numbers to each other, it is much easier if they are in the same form.   typically, the best form in which to evaluate rational numbers is in decimals.   in order to convert a percent to a decimal, you would divide the given percentage by 100.   you can also accomplish the conversion by moving the decimal point over two places to the left.   for example, the decimal value of 80% is 80/100, or 0.8.   in order to convert a fraction to a decimal, you need to divide the numerator by the denominator.   for example, 3/4 is 0.75.   so, for choice (b) 0.5 3/4 (0.75), 80% (0.8) is the only choice in which the numbers are in order from least to greatest.  

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

cretdit to source

when functions are first introduced, you will probably have some simplistic "functions" and relations to deal with, usually being just sets of points. these won't be terribly useful or interesting functions and relations, but your text wants you to get the idea of what the domain and range of a function are. small sets of points are generally the simplest sorts of relations, so your book starts with those.

step-by-step explanation:

state the domain and range of the following relation. is the relation a function?

{(2, –3), (4, 6), (3, –1), (6, 6), (2, 3)}

the above list of points, being a relationship between certain x's and certain y's, is a relation. the domain is all the x-values, and the range is all the y-values. to give the domain and the range, i just list the values without duplication:

domain: {2, 3, 4, 6}

range: {–3, –1, 3, 6}

(it is customary to list these values in numerical order, but it is not required. sets are called "unordered lists", so you can list the numbers in any order you feel like. just don't duplicate: technically, repetitions are okay in sets, but most instructors would count off for this.)

while the given set does indeed represent a relation (because x's and y's are being related to each other), the set they gave me contains two points with the same x-value: (2, –3) and (2, 3). since x = 2 gives me two possible destinations (that is, two possible y-values), then this relation is not a function.

note that all i had to do to check whether the relation was a function was to look for duplicate x-values. if you find any duplicate x-values, then the different y-values mean that you do not have a function. remember: for a relation to be a function, each x-value has to go to one, and only one, y-value.

state the domain and range of the following relation. is the relation a function?

{(–3, 5), (–2, 5), (–1, 5), (0, 5), (1, 5), (2, 5)}

i'll just list the x-values for the domain and the y-values for the range: