The sum of the squares of two consecutive positive odd integers is 202. Find the numbers. Let statement and algebraic solution please. Thanks!

Step-by-step explanation:

the integers are x and x+2

x^2 + x^2 + 4x + 4 = 202

2x^2 + 4x -198 = 0

x^2 + 2x -99 = 0

x^2 + 11x -9x -99 = 0

x(x + 11) -9(x + 11) = 0

(x-9)(x+11) = 0

x = 9 or -11

x+ 2 = 11 or -9

9 or 11

-9 or -11

9.55 degrees.

step-by-step explanation:

the given angle is

1 cycle is equal to 2π radians. so 4π will be equal to two cycles.

5.166667π-4π = 1.166667π

hence, this angle goes a little more than negative x axis.

1.166667π-π= 0.166667π

hence, the reference angle is 0.166667π radians.

1 radian = 57.2958 degrees

now, in degrees, this should be equals to 9.55 degrees.

45

step-by-step explanation:

to find a percentage, add a decimal in front and multiply it by the other number.

.25 times 180= 45