A particle traveled the distance of 6.6× meters a a rate of 3.3×. If distance equals rate times time, how many seconds did it take the particle to travel the specified distance?
A. 5.0x seconds
B. 2.0x seconds
C. 2.0x seconds
D. 5.0x seconds

Distance (D) equals rate (R) times time (T): D = R x T

=> T = D/R = 6.6 x 10^-19/(3.3 x 10^-34) = 2 x 10^15 (m)

=> Option B is correct

Hope this helps!

:)

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.

this is a good question! i’ll do some research and what i find, i’ll contact you asap when i have something! ✊