PLEASE HELP
( velocity - on a graph )

a) v_avg = k

b) 0.034 km/h

Step-by-step explanation:

a) The average velocity is given by the displacement over the time:

  (1)

Δx is the area under the line. In this case you can consider two areas. Firs, from t=0 t0 t=30 and from t=30 to t=50:

S1 = 30k

S2 = 20k/2 = 10k

Then, the total surface is:

S = S1+S2 = 50k

The average speed is:

v_avg = (50k)/(50s)= k

b) The value of k can be determined by using the expression for the total area under the line, which is the total displacement of the car S=1.7 km:

S=50k=1.7km

k=(1.7km)/(50k)=0.034km/h = 34 m/h

the mistake in the pattern is that :

b. the decimal point was moved one too many place values each time

the correct pattern could be made by :

b. moving the decimal point to the right the same numbers of place values as the exponents

so a parallelogram is just like a square base times height. multiply 40 and 39 to get 1560 inches.

a triangle is base times height divided by two. so multiply 7.9 and 5 and then divide it by 2 to get 19.75inches.

the kite can be split into two separate triangles and added together to get the total area. 30 x 4 /2 which equals 60. make sure to double it for the two triangles making 120.