Three geometric sequences are given below.
Sequence A: 160, 40, 10, 2.5, ...
Sequence B: -21, 63, -189, 567, ...
Sequence C: 8, 12, 18, 27, ...
Order the sequences from least common ratio to greatest common ratio.
Sequence A
Sequence C
Sequence B

B, A, C

Step-by-step explanation:

Calculating the common ratio for each sequence

A → r = = = 0.25

B → r = = - 3

C → r = = 1.5

B, A, C ← from least to greatest common ratio

75%

step-by-step explanation:

step-by-step explanation:

part a. the differences are decreasing, so we know the sequence is not arithmetic. the ratios are constant (=3/4), so we know the sequence is geometric.

part b. from part a, we know the common ratio is 3/4, so each term is 3/4 of the one before. the initial term is the number of gallons at h=1.

g[h] = (3/4)·g[h-1]

g[1] = 384 . . . . initial value required for a recursive definition

part c. the general formula for a geometric sequence is

a[n] = a[1]·r^(n-1)

we have a[1] = 384, r = 3/4, and the term number given by h. the formula that follows is

g[h] = 384·(3/4)^(h-1)

part d. filling in the value and doing the arithmetic, we have

g[12] = 384·(3/4)^11 ≈ 384·0.042235136 ≈ 16.2183 . . gallons

part e. each gallon is 4 quarts, so

16.2183 gal × 4 qt/gal = 64.8732 qt