Which equation represents a line that passes through (2. - 1/2) and has a slope of 3?

y-2 = 3(x + 1/2)

y-3 = 2(x + 1/2)

y + 1/2 = 3(x - 2)

y + 1/ 2 = 2(x - 3)

y + 1/2 = 3(x - 2)          This matches the 3rd answer choice.

Step-by-step explanation:

Use the point-slope formula for the equation of a straight line that passes through the point (h, k) and has a slope of m:

y - k = m(x - h) becomes:

y + 1/2 = 3(x - 2)          This matches the 3rd answer choice.

360/29

step-by-step explanation:

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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