You have three pieces of paper in an envelope. One piece of paper has the number 1 written on it, another has the number 2 written on it, the other has the number 3 written on it. You draw and replace a piece of a paper three times. What is the probability that it’s in this order (1,2,3) or this order (2,2,2)?

See below in bold.

Step-by-step explanation:

Prob( 1 is first drawn) = 1/3

Prob(2 is second) = 1/2

Prob(3 is 3rd) = 1/3

So probability of 1,2,3 is (1/3)^3 = 1/27.

(2,2,2) is the same probabiilty 1/27.

b is 38 degrees.

a is 52 degrees.

this is because if b is 38 and a is 14 degrees more than b than 38+14=52 and 52+38=90 degrees. hope this .

0.16 or 16%

step-by-step explanation:

lets take a coin for example.

if you toss it twice, it has a 1/4 chance of landing on heads both times because 1/2 * 1/2 is 1/4.

with the cards, the chance of picking dog is 0.4. having two people pick one is like picking a card twice in a row. so 0.4 * 0.4 is 0.16, or 16%