The average mark of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are 148, 102, 15zs2. What is the average of the extracted scores that are extreme values (outliers)

Solution:

The average marks of candidates in an aptitude test was 128.5 with a standard deviation of 8.2. Three scores extracted from the test are; 148, 102 and 152.

To find : average of the extracted scores that are the extreme values (outliers)

The average marks of candidates in an aptitude test was 128.5

=> Mean = 128.5

Standard Deviation = 8.2

outlier will be out sides   then range    Mean  ± 3* SD

128.5 ± 8.2 × 3

= 128.5 ± 24.6

Range is   ( 103.9  ,  153.1)

102 is outside this range

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation: