In an all boys school, the heights of the student body are normally distributed with a mean of 71 inches and a standard deviation of 5 inches. What percentage of the students are shorter than 76 inches tall, to the nearest tenth?

15.87%

Step-by-step explanation:

First thing here is that we calculate the z-score which corresponds to 76

mathematically;

z-score = (x-mean)/SD

mean = 71 and SD = 5

plugging these values, we have;

z = (76-71)/5 = 5/5 = 1

Now, we want to firstly get the probability that we have a student shorter than 76 inches

The probability we want to calculate is P(z<1)

we can get this using the z-score table directly

That would be 0.15866

In percentage that is 15.866% which is 15.87% to the nearest tenth

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5

f(x)=4

step-by-step explanation: