Quadrilateral DEFG has vertices at D(6,1), E(2,4), F(-5,4) and G(-1,1). What is the area of the quadrilateral?

Area of the quadilateral = 35 square units.

Step-by-step explanation:

The coordinates of the quadilateral DEFG are given as

D(6,1), E(2,4), F(-5,4) and G(-1,1).

To obtain the area, we need the length of each of the quadilateral's sides.

The length of each side is the distance between the coordinates given.

The distance between two coordinates (x₁, y₁) and (x₂, y₂) is given as

d = √[(y₁ - y₂)² + (x₁ - x₂)²]

The lengths of the quadilateral's sides include DE, EF, FG and GD

DE = distance between D(6,1) and E(2,4)

DE = √[(1 - 4)² + (6 - 2)²]

DE = √(9 + 16) = 5 units

EF = distance between E(2,4) and F(-5,4)

EF = √[(4 - 4)² + (2 - -5)²]

EF = √(0 + 49) = 7 units

FG = distance between F(-5,4) and G(-1,1).

FG = √[(1 - 4)² + (-1 - -5)²]

FG = √(9 + 16) = 5 units

GD = distance between G(-1,1) and D(6,1)

DE = √[(1 - 1)² + (-1 - 6)²]

DE = √(0 + 49) = 7 units

The dimensions of the quadilateral show that it is a rectangle.

The area of a rectangle = (length) × (width)

Length = 7 units

Width = 5 units

Area of the quadilateral = 7 × 5 = 35 square units.

Hope this Helps!!!

yor answer is 7/6 times 5

step-by-step explanation:

because 1.2 isnt half of 6 duh