A survey of 300 union members in New York State reveals that 112 favor the Republican candidate for governor. Construct the 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate. Please show written work for question a to c below. a) Find critical value(s). b) "Find the Margin of Error" c) Find confidence interval for the problem.

a) z = 2.327

b) The margin of error is of 0.065.

c) The 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate is (0.3083, 0.4383).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.

In which

z is the zscore that has a pvalue of .

For this problem, we have that:

a) 98% confidence level

So , z is the value of Z that has a pvalue of , so is the critical value.

b)

The margin of error is:

So, applying to this question:

The margin of error is of 0.065.

c) Find confidence interval for the problem.

The 98% confidence interval for the true population proportion of all New York State union members who favor the Republican candidate is (0.3083, 0.4383).

e^-kt = n/n0 = 0.79  

-kt = ln 0.79  

t = - ln 0.79/0.0001  

= 2357 years

step-by-step explanation: