The triangular prism shown below is 6 \,\text{cm}6cm6, start text, c, m, end text wide and 4\,\text{cm}4cm4, start text, c, m, end text deep. The vertical height is 7\,\text{cm}7cm7, start text, c, m, end text. What is the length of the side edge, sss, of the triangular prism? Round your answer to the nearest tenth.

Question :

The triangular prism shown below is 6 cm wide and 4 cm deep. The vertical height is 7 cm. What is the length of the side edge, s, of the triangular prism? Round your answer to the nearest tenth.

7.62cm

Step-by-step explanation:

Given the following :

Width = 6cm

Depth = 4cm

Vertical height = 7cm

Splitting the face of the prism into two:

Thus the width becoming 6cm/2 = 3cm and vertical height = 7cm

Using Pythagoras ;

The side edge 's' equals

s^2 = width^2 + height^2

s = √(width^2 + height^2)

s = √(3^2 + 7^2

s = √9 + 49

s = √58

s = 7.62cm

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: