A plane is descending into an airport. When its altitude is 3 1/2 miles, it is 250 miles from the airport. When its altitude is 1 mile, it is 75 miles from the airport. At 2 1/2 miles, it is 175 miles from the airport. Problem 6 a. If the pilot follows the same pattern, what will the plane's altitude be at 25 miles from the airport? *

1/2 miles

Step-by-step explanation:

Given the following:

Altitude (miles) - - - - - - - - - - distance (miles)

3 1/2 - - - - - - - - - - - - - - - - - - - 250

2 1/2 - - - - - - - - - - - - - - - - - - - - 175

Calculate the plane's altitude at 25miles from the airport

7/2 = 250

5/2 = 175

(7/2 - 5/2) miles = (250 - 175)miles

1 mile = 75 miles

From the above, the plane craft 's altitude reduces by 1 mile for every 75 miles moved

Therefore, at a distance of 25 mile from the airport,

Distance moved = (250 - 25)miles = 225miles

225miles / 75 miles = 3

Therefore, the altitude will reduce by 3 miles from the initial altitude at 250 miles

Therefore,

( 3 1/2 - 3) miles = 1/2 miles

Therefore, the plane craft will have an altitude of 1/2

or

step-by-step explanation:

for volume, add base x height x width