1
Solve the inequality and graph its solution:
-1457
A
13 14
-33-36-31-14
-
14
21
38
35
B. 14
-33-28 -21-14
-T
?
14
21
35
C.
3-14
1
-33 -28 -21-14
-
0
14
21
38
33
D.
-14
--33-28 -21 -14 -
0
14
21
38 33

where are the graphs?

step-by-step explanation:

60: 45 =12: 9 =4: 3 so the answer is 4: 3

0 and 5 minutes

step-by-step explanation:

given that one morning eight buses arrive late by the number of minutes given below:

0 8 2 6 9 2 0 7 8

write these in ascending order

0   0 2 6 7 8 8 9

in the afternoon two more buses arrive at the bus stop say by x and y minutes late.

total number of buses = 10

median = average of 4th and 5th after arranging in ascending order

since 4th entry is 6, the values of x and y should be below 6

also given 0 is the mode so either x or y or both should be 0 because then only 0 gets the maximum frequency and hence mode

thus we have

0 0 0 2 6 7 8 8 9 and another unknown entry which is below 6.

since median is 3.5, we have the unknown entry to be 5 only because then only median =( 2+5)/2

thus the after noon buses were late by 0 and 5 minutes.