Analyzing the function below, compare and contrast the two functions in each problem situation. Be sure to use complete sentences in your comparison. Be sure to include a discussion of similarities and differences for the periods, amplitudes, y-minimums, y-minimums, and any phase shift between the two graphs.

1. Y=3sin(2x) and Y=3cos(2x)

2. Y=4sin(2x-π) and Y=cos(3x-π/2)

Step-by-step explanation:

1) Y=3sin(2x)  and

Y=3cos(2x)

a) Both have same amplitude which is 3 .

b ) They have same period as they have same angular frequencies which is 2 .

c ) But their initial phases differ by π /2  radian or 90° .

2. Y=4sin(2x-π) and

Y=cos(3x-π/2)

a ) Their amplitudes are different . One has amplitude of 4 and the other have amplitude of 1 .

b ) They have different angular frequencies so their time periods too are different .

c ) They have different initial phase difference . That differ by 90° .

incomplete question. how do you expect anyone to you when you do not post the question in its entirety?

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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