There were 23 students running in a race. How many different arrangements of first, second, and third place are possible?

10626 different arrangements

Step-by-step explanation:

As we have a total of 23 students and we want to form groups of 3, where the order of the 3 students matters, we can solve this problem using a permutation of 23 choose 3.

The formula for a permutation of n choose p is:

P(n,p) = n! / (n-p)!

So, using n = 23 and p = 3, we have:

P(23,3) = 23! / (23-3)! = 23! / 20! = 23 * 22 * 21 = 10626

So we have a total of 10626 different arrangements of first, second and third place.

two data sets with the same median will not have the same varaibility

step-by-step explanation:

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.