A square stained window is divided into four congurent traiangular sections by iron edging to represent seasons of the year. Each diagonal measures 9 inches. What is the total length of iron edging needed to create the sqaure frame and two diagnols?

Total length of iron needed to make the square frame and two diagonals =  43.44 in (Approx)

Step-by-step explanation:

Given:

Length of diagonal = 9 in

Find:

Total length of iron needed to make the square frame and two diagonals.

Computation:

Area of square = 1/2(diagonal)²

Area of square = 1/2(9)²

Area of square = 40.5 in²

Area of square = Side × Side

40.5 in² = Side × Side

Side = 6.36 (approx)

Total length of iron needed to make the square frame and two diagonals = Permeter of square + (2 × diagonal)

⇒ (4 × 6.36) + (2 × 9)

⇒ (25.44) + (18)

⇒ 43.44 in

Total length of iron needed to make the square frame and two diagonals =  43.44 in (Approx)

(a) the volume of the cone is 20/3 in3

hence, option a is correct.

the square root of 16 is 4.

4*4 = 16