Find a least-squares solution of Axequalsb by (a) constructing the normal equations for ModifyingAbove Bold x with caret and (b) solving for ModifyingAbove Bold x with caret. Aequals[Start 3 By 2 Matrix 1st Row 1st Column negative 1 2nd Column 2 2nd Row 1st Column 2 2nd Column negative 3 3rd Row 1st Column negative 1 2nd Column 3 EndMatrix ], bequals[Start 3 By 1 Matrix 1st Row 1st Column 16 2nd Row 1st Column 4 3rd Row 1st Column 8 EndMatrix ](a) Construct the normal equations for ModifyingAbove Bold x with caret. [Start 2 By 2 Matrix 1st Row 1st Column nothing 2nd Column nothing 2nd Row 1st Column nothing 2nd Column nothing EndMatrix ][Start 2 By 1 Matrix 1st Row 1st Column x 1 2nd Row 1st Column x 2 EndMatrix ]equals[Start 2 By 1 Matrix 1st Row 1st Column nothing 2nd Row 1st Column nothing EndMatrix ](Simplify your answers.)

a box 3 3/4 feet long or 4+ feet.

step-by-step explanation:

the largest number of the four options is 1.8 x 10-2

you have it in scientific notation.

1.80 x 10-6   = 0.00000180

1.80 x 10-4   = 0.000180 (bigger, or "less small", than the former one)

so

1.8 x 10-2       = 0.0180. as you see. the "less small", or the biggest one of them all.

as you have negative exponent, it means you are dividing 1.8 by 100 (i.e. moving the dot towards left, two times).

if you had positive exponent for the scientific notation, power of tenths, you would be multiplying times 100 (moving the dot towards right) as below:

1.8 x (10)2 = 180

so. if you have negative exponent in scientific notation, move the dot toward left. if it is positive, toward right as many times the exponent tells you.

98%

step-by-step explanation:

something over 10 so ? /10

step-by-step explanation: