If PQ is tangent to circle R at point Q and PS is
tangent to ⊙R at point S, what is the perimeter
of quadrilateral PQRS?

Perimeter of the quadrilateral PQRS is 25 units

Step-by-step explanation:

From the figure attached,

PQ is a tangent to the given circle so m∠PQR = 90°

Now we apply Pythagoras theorem in the ΔPQR,

PR² = PQ² + QR²

(PT + TR)²= PQ² + 5²

(4 + 5)² = PQ² + 25

81 = PQ² + 25

PQ = √(81 - 25)

     = √56

     ≈ 7.5 units

PQ ≅ PS ≅ 7.5 units

[Since measures of tangents drawn from a point to a circle are always equal]

Perimeter of PQRS = PQ + QR + RS + PS

                                = 7.5 + 5 + 5 + 7.5

                                = 25 units

Therefore, perimeter of the quadrilateral PQRS is 25 units.

answer: i don't understand. what are the options

step-by-step explanation: