The angle 01 is located in Quadrant II, and sin(01) =
9/41
What is the value of cos(01)?
Express your answer exactly.
cos(01) =

-40/41

Step-by-step explanation:

Since we know 'cos' involves the Adjacent and Hypoteneus sides, we will need to solve for the 'Adjacent' side of the triangle using the Hypoteneus Theorem.

41² = 9² + a²

a = 40.

However, this is in quadrant II, so when finding the 'cos' value, this side is -40.

Cosine is A/H, giving is:

cos(01) = -40/41

(1,4) is on graph of f(x)

f(1) = 4

so 1/4 f(x)

1/4 f(1)

1/4. ×4

1

so point for function 1/4. f(x) is (1,1)