Given:

m∠QPS=107∘

m∠RPS=4x+27∘

m∠QPR=9x-115∘

Find m∠QPR

**This was on Khan Academy, so please hurry lol**

m∠QPR = 20°

Step-by-step explanation:

If we make a sketch of the triangle, it will be observed, that line R bisects angle P.

Considering Triangle, ΔQPS;

∠QPS=107∘

Considering triangle, QPR;

∠QPR=9x-115∘

Considering triangle, RPS;

∠RPS=4x+27∘

Thus, ∠RPS + ∠QPR = ∠QPS

4x+27° + 9x-115° = 107°

13x - 88° = 107∘

13 x = 107∘ + 88∘

13x = 195°

x = 195°/13

x = 15°

m∠QPR = 9x - 115°

= (9 x 15) - 115°

= 135° - 115°

= 20°

Therefore, m∠QPR = 20°

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.