Jake is wrapping a gift that is in a box with the following dimensions.

Length: 12 inches
Width: 4 inches
Height: 8 inches

Havana is wrapping a gift whose box's dimensions are all twice the length of the lengths in Jake's box. How many times larger is the surface area of Havana's box than Jake's box?

Because you are looking for square inches of wrapping paper, you are looking for the surface area of the box. A three-dimensional box has a top and bottom that are the same size, a front and back that are the same size, and 2 sides that are the same size...or SA = 2(top/bottom area) + 2(front/back area) + 2(side/side area). Our equation fills in nicely like this:

SA = 2(6 * 14) + 2(6 * 8) + 2(14 * 8)

SA = 2(84) + 2(48) + 2(112)

SA = 168 + 96 + 224

SA = 488 square inches of paper to wrap the box.

Step-by-step explanation:

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer: -2+√x,-2-√x

i hope this , i don't know if you're looking for a pair or not.