The center of a circle is at (-5 12) and it has a radius of 16. what is the equation of the circle?

(x+5)^2+(y-12)^2=256
(x+5)^2+(y-12)^2=4
(x-5)^2+(y+12)^2=256
(x-5)^2+(y+12)^2=4

(x+5)^2+(y-12)^2=256

Step-by-step explanation:

Comparing the given (x+5)^2+(y-12)^2=256

to                                   (x - h)^2 + (y - k)^2 = r^2,  

we see that h must be -5, k must be 12 and r must be 16.  This is the desired equation of the circle with center at (-5, 12) and radius 16.

2.   2 3/5.

3.   2 1/2.

step-by-step explanation:

6 - 3 2/5

= 6 -   17/5

= 30/5 - 17/5

= 13/5

= 2 3/5 (answer).

5 1/4 - 2 3/4

= 21/4 - 11/4

= 10/4

= 2 1/2 (answer).