Jumpy-Jump inserts claim to increase a basketball player's vertical leap by about 2 inches. The data show the

vertical leaps(in inches) for several players with and without the inserts.

With insert: 24 27 28 35 30 36 31 36

Without: 23 27 27 33 31 36 30 35

State the null hypothesis

Step-by-step explanation:

Hello!

The claim is that the insert increases the basketball player's vertical leap by about two inches.

To test this they measured the vertical leap of several players with and without inserts. Since both variables X₁: vertical leap of a basketball player without insert and X₂: vertical leap of a basketball player with an insert were measured over the same experimental unit, they are not independent but pairs.

This is an example of a paired sample test. I'll determine the difference as Xd= X₁ - X₂

The parameter of interest is the population mean of the difference between the vertical leap of the basketball players without the insert and the vertical leap with insert, symbolically μd

If the claim of the company is correct then the value of the parameter should be μd = 2

The hypotheses are:

H₀: μd = 2

H₁: μd ≠ 2

I hope this helps!

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).