Lesson Posttest

Re

Question 4

Points 2

Roselin has a bag of fruit. The bag contains 5 apples, 9 peaches, and 5 oranges. How

many outcomes are possible in a single draw of fruit from the bag?

O

O

O

O

1

Step-by-step explanation:

Probability = number of fruit type/total number of fruit. Total number of fruit = 5 + 9 + 5 = 19.

The probability of drawing an apple is P(apple) = number of apples/total number of fruit = 5/19.

The probability of drawing a peach is P(peach) = number of peaches/total number of fruit = 9/19

The probability of drawing an apple is P(orange) = number of oranges/total number of fruit = 5/19

The probability of drawing either an apple, peach or orange at the first draw of fruit from the bag is

P(apple or peach or orange) =  P(apple) + P(peach) + P(orange)

                                               = 5/19 + 9/19 + 5/19

                                               = (5 + 9 + 5)/19

                                               = 19/19

                                               = 1

3 is greater then both of those numbers

c - they will have the same distribution

step-by-step explanation:

this is the only one that could make sense. : )